P>PowerBuilder是当前得到广泛应用的C/S数据库前端开发工具,
在使用PB的过程中,经常遇到要将数字进行英文或中文的大写转换，尤其是在处理金额的时候，本文整理了我在实践中用到的转换方法，提供给大家参考。
一、 英文大写转换
以下是进行英文大写转换的函数内容，函数名为dtoe：
//****** 阿拉伯数--- $#@62;英文数 ******
string aa,bb,T1,T2,T3,B,W,CC,a1
decimal a=0,c=0,a2
INTEGER V,M
aa="ONE TWO THREE FOUR
FIVE SIX SEVEN "+&
"EIGHT NINE TEN ELEVEN TWELVE
THIRTEEN FOURTEEN FIFTEEN "+&
"SIXTEEN SEVENTEENEIGHTEEN NINETEEN "
bb="TWENTY THIRTY FORTY FIFTY SIXTY SEVENTYEIGHTY NINETY "
//**** 进入时 --- $#@62; t
T=round(t,2)
T1=STRING(T)
DO WHILE POS(T1,",")$#@60; $#@62;0
V=POS(T1,",")
T1=MID(T1,1,V - 1)+MID(T1,V+1)
LOOP
T2=" "
T3=T1
IF POS(T3,".")$#@60; $#@62;0 THEN
V=POS(T3,".")
T1=MID(T3,1,V - 1)
T2=MID(T3,V+1)
END IF
T1=SPACE(10 - LEN(T1))+T1
CC=T1
B=" "
W=" "
M=9
//*** 整数处理 ***
do while m $#@62;0
if MID(cc,m+1,1)=" " then
exit
end if
if INTEGER(MID(cc,m - 1,3))$#@60; $#@62;0 then
if m=6 then
W=" THOUSAND "+w
else
if m=3 then
W=" MILLION "+w
end if
end if
A=INTEGER(MID(cc,m,2))
//*** 小于 100 的数 ***
if a$#@60; $#@62;0 then
if a$#@60; 20 then
B=RIGHTtrim(MID(aa,(a - 1)*9+1,9))
else
A1=STRING(a,00)
A2=INTEGER(MID(a1,1,1))
b=RIGHTtrim(mid(bb,(a2 - 2)*7+1,7))
a2=INTEGER(MID(a1,2,1))
if a2$#@60; $#@62;0 then
B=RIGHTtrim(b+"-"+MID(aa,(a2 - 1)*9+1,9))
end if
end if
W=b+w
end if
A=INTEGER(MID(cc,m - 1,1))
//*** 100--999 的数 ***
if a$#@60; $#@62;0 then
b=RIGHTtrim(mid(aa,(a - 1)*9+1,9))+" HUNDRED "
if w$#@60; $#@62;" " and m=9 then
b=b+"AND "
end if
w=b+w
end if
end if
m=m - 3
LOOP
//*** 小数处理 ***
if w=" " then
w="ZERO "
end if
if t2$#@60; $#@62;" " AND T2$#@60; $#@62;"00" then
w=trim(w)+" & "+t2+"/100"
end if
//*** 结果 --- $#@62; w
return w
二、中文大写转换
以下是进行中文大写转换的函数内容，函数名为dtormb：
decimal y
string je,x,hz1,hz2,e,h,f,m
int b,a
y=mje
X rim(string(Y))
B = len(X)-3
A = 1
E = mid(X,A,1)
HZ2 = 零壹贰叁肆伍陆柒捌玖
HZ1 = 仟佰拾亿仟佰拾万仟佰拾元
JE =
do while E$#@60; $#@62;.
H = mid(HZ2,integer(E)*2+1,2)
F = mid(HZ1,24 - (B - A)*2 - 1,2)
if E$#@60; $#@62;0 or (E=0 and (F=亿 or F=万 or F=元)) then
JE = trim(JE)+H+F
else
JE = trim(JE)+H
end if
A = A+1
E = mid(X,A,1)
loop
A = A+1
E = mid(X,A,1)
H = mid(X,A+1,1)
if E=0 and H=0 then
JE = JE+整
else
if E=0 then
JE = JE+零+mid(HZ2,integer(H)*2+1,2)+分
else
if H=0 then
JE = JE+mid(HZ2,integer(E)*2+1,2)+角整
else
JE = JE+mid(HZ2,integer(E)*2+1,2)
+角+mid(HZ2,integer(H)*2+1,2)+分
end if
end if
end if
B = len(JE)
A = 1
do while A$#@60; B
M = mid(JE,A,4)
if M=零元 or M=零万 or M=零亿 or M=零零 then
JE = mid(JE,1,A - 1)+trim(mid(JE,A+2,40))
A = A - 2
B = B - 2
end if
A = A+2
loop
return JE
